Saturday, March 6, 2010

Internal resistance


Before the switch is turned on
  • The battery does not supply current to the light bulb
  • Voltmeter reading = E.m.f. of battery

After the switch is turned on
  • The battery supplies current which flows around the circuit
  • Voltmeter measures the potential difference across the terminals of the battery
  • The voltmeter reading drops due to internal resistance of the battery
EMF = IR + Ir
EMF = V + Ir
EMF = I (R + r)

where EMF = electromotive force [V]
I = current flowing through the circuit [A]
R = total resistance of the circuit [Ω]
r = internal resistance of the batteries [Ω]
V = potential difference of the circuit [V]


Worked example:

What is the internal resistance of a battery if its emf is 12 V and the voltage drop across its terminals is 10 V when a current of 4 A flows in the circuit when it is connected across a load?

Solution:
E = V + Ir

12 = 10 + 4(r)

r =0.5

0 comments:

Post a Comment

Note: Only a member of this blog may post a comment.