The current flows through each bulb/resistor is the same

I = I1 = I2

The potential difference across each resistor depends directly on its resistance. The potential difference supplied by the dry cells is shared by all the resistors.

V = V1 + V2

where V is the potential difference across the battery

If Ohm’s law is applied separately to each resistor, we get :

V = V1 + V2

IR = IR1 + IR2

If each term in the equation is divided by I, we get the effective resistance

R = R1 + R2

Worked example :

There are two resistors in the circuit shown. Resistor R1 has a resistance of 1Ω. If a 3V voltage causes a current of 0.5A to flow through the circuit, calculate the resistance of R2.

solution :

V = IR

3=0.5(1+R2)

R2 = 5Ω

3 days ago

## 1 comments:

Greetings from Poland :-)

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